For decreasing function if a<b ..f(a)>f(b) and for increasing funtions... f(a)<f(b)...
option A :
Range of p and q : (-inf,0)...:decreasing function...so if p<q then f(p)>f(q)...

...which is the opposite of the given option....hence A is false...
option B :
Range : (1,inf).....:increasin'....so if p<q ,...f(p)<f(q)...

...so B is right
option C :
Range : (0,1)...decreasin'...so if p<q ....f(p)>f(q)....

....so C is incorrect
option D:
Range ; (0,1)....decreasing'...if p>q...f(p)<f(q)...

..so D is also incorrect.
So the only correct option is B