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hash_include (381)

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Olaaa!! Perrrfect answer. 59  [102 rates]

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1.
\sum_{i=1}^{n} \frac 1 {\frac {r(r+1)}{2}}

= 2.  \sum_{i=1}^{n} \frac 1{r(r+1)}

= 2. \sum_{i=1}^{n} \frac {(r+1) - r }{r(r+1)}

= 2. [\sum_{i=1}^{n} \frac 1 {r} - \sum_{i=1}^{n} \frac 1 {r+1}]

= 2[ (\frac 1 1 - \frac 1 2) + (\frac 1 2 - \frac 1 3) ....... + (\frac 1 n - \frac 1 {n+1})]

everything except the first and last term gets cancelled

= 2 ( 1 - \frac 1 {n+1})

= \frac {2n}{n+1}

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