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Ask iit jee aieee pet cbse icse state board experts Discussion Response Post to: H.C.VERMA VOL 1 PG 99 Q 29(FRICTION)
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waterdemon (4732)

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Olaaa!! Perrrfect answer. 866  [1067 rates]

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29)

The Force which may cause the tendency of motion or the
motion in the body is its own Weight & the applied horizontal
force of 15N.

We have Resultant of the forces as:
Fres = (20)2+(15)2
Fres =
625
Fres = 25N.

In a Direction of:
@ = Tan-1(15/20) = Tan-1(3/4) = 370 with the Vertical.

The Friction will always oppose the tendency of  Relative
motion and will act in a direction opposite of Resultant F.
F = Force.

Now for the acceleration to be minimum:
Minimum Force required: (N=40=F applied against the wall)
Fmin = F - uN
Fmin = 25 - (0.5)40
Fmin = 5N.

So the minimum Acceleration will be:
Fmin=mamin
5 = 2(amin)
amin = 2.5m/s2.

Since @ = 370 with the vertical so @ = 530 with the
Horizontal.

[Thumb - HCV friction.JPG]

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