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Discussion Response Post to:
H.C.VERMA VOL 1 PG 99 Q 29(FRICTION)
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Message
27 Mar 2008 09:51:06 IST
Subject:
Re:H.C.VERMA VOL 1 PG 99 Q 29(FRICTION)
waterdemon
(
4732
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Forum Expert
Blazing goIITian
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29)
The Force which may cause the tendency of motion or the
motion in the body is its own Weight & the applied horizontal
force of 15N.
We have Resultant of the forces as:
F
res
=
(20)
2
+(15)
2
F
res
=
625
F
res
= 25N.
In a Direction of:
@ = Tan
-1
(15/20) = Tan
-1
(3/4) = 37
0
with the Vertical.
The Friction will always oppose the tendency of Relative
motion and will act in a direction opposite of Resultant F.
F = Force.
Now for the acceleration to be minimum:
Minimum Force required: (N=40=F applied against the wall)
F
min
= F - uN
F
min
= 25 - (0.5)40
F
min
= 5N.
So the minimum Acceleration will be:
F
min
=ma
min
5 = 2(a
min
)
a
min
= 2.5m/s
2
.
Since @ = 37
0
with the vertical so @ = 53
0
with the
Horizontal.
Hope you find it useful.
Rate if useful.
Cheers!!!!!!!!!!!!!
Always available for help !
But Remember Don't hesitate to ask a good Question but
Be damn serious for Questioning a weak one.
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