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![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Mar 2008 10:17:49 IST
Accepted Answer [?]
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B ) 1
cos-1x +cos-1y +cos-1z = 
cos-1x +cos-1y = -cos-1z
cos [ cos-1x +cos-1y ] = cos [ -cos-1z]
xy - [(1-x2)(1-y2)]1/2 = -z
=> x2+y2+z2+2xyz = 1
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