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Werewolf (333)

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Olaaa!! Perrrfect answer. 55  [84 rates]

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Imagine the figure in your mind

Applying sin law in triangle DBC we have

BD/sinheta = BC/sin (pi-3heta/2) =>[BD/sinheta]sin (pi-3heta/2) = BC....(i)

Apply sine law in triangle ADB we have

AD =[sinheta/2/sin(pi-2heta)] BD......(ii)

subsitute values of BC and BD from equation (i) and (ii) in BC= BD+AD

we get,

[BD/sinheta]sin (pi-3heta/2) = BD + [sinheta/2/sin(pi-2heta)] BD

BD gets cancelled from both sides , solve for heta


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