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meenugouri (0)

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Olaaa!! Perrrfect answer. 0  [0 rates]

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45 ml of 0.0325 M  HCN solution is titrated with 0.0200 M  NaOH solution.( Ka of  HCN =6.2  x  10 power - 10 )
1)  calculate volume of NaOH used in titration in order to reach equivalence point ?
 
2) What is the  pH of the solution at equivalent point ?
 
3) What is molar concentration of CN- at equivalent point ?
 
    
 

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