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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Mar 2008 13:19:39 IST
Accepted Answer [?]
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Apply sine rule in triangle ABD
AD/sinB = (a/2)/sinA/3....(1)
Apply sine rule in triangle ADC
AD/sinC = (a/2)/sin2A/3....(2)
Divide equation (1) and (2)
ADsinB/ADsinC = (a/2)sinA/3/(a/2)sin2A/3
sinB/sinC = sinA/(2sinA/3cosA/3)
sinB/sinC = 1/2secA/3
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