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Blazing goIITian

total posts: 1025
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since they have common acceleration
they can be considered as a system
now for the system of A&B
mgsin37 -

₂ mgcos37 = ma
gsin37 -

₂ gcos37 = a
simplifying we get
6 - 8

₂ = a ---------------------(1)

now for block A
mgsin37 +

₁ mgcos37 - ma (pseudo force)= 0
gsin37 +

₁ gcos37 = a
simplifying we get
a = 6 + 8

₁ --------------------------(2)
from 1 and 2
6+8

₁ = 6 - 8

₂
or

₁ = -

₂

therefore it is option B

correct me if i"m wrong

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