IIT Exam – IIT-JEE,AIEEE Exams,IIT Engineering 2010, IIT Preparation 2010, IIT Test Series,IIT JEE Sample Paper, AIEEE 2010, Engineering Entrance Examination, Online Test Series, Online Coaching, Engineering Entrance Experts, Education Forum, Online Test Papers

BALGANESH

since they have common acceleration
they can be considered as a system
now for the system of A&B
mgsin37 -

₂ mgcos37 = ma
gsin37 -

₂ gcos37 = a
simplifying we get
6 - 8

₂ = a ---------------------(1)

now for block A
mgsin37 +

₁ mgcos37 - ma (pseudo force)= 0
gsin37 +

₁ gcos37 = a
simplifying we get
a = 6 + 8

₁ --------------------------(2)
from 1 and 2
6+8

₁ = 6 - 8

₂
or

₁ = -

₂

therefore it is option B

correct me if i"m wrong