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Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: Properties Of Triangles
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Werewolf (333)

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Olaaa!! Perrrfect answer. 55  [84 rates]

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Since A+B+C=pi

=> A+B =pi-C = pi-pi/3 = 2pi/3.....[ the angles should satisfy this condition]

Now we have ,

a/b = tan5pi/12

=> sinA/sinB = tan5pi/12

=> sinA/sinB = ( sin5pi/12 )/( cos5pi/12 )

=> sinA/sinB = ( sin5pi/12 )/( sinpi/12 )     [ cos5pi/12 = sinpi/12]

=> sinA/sinB = ( sin7pi/12 )/( sinpi/12 )     [ sin5pi/12 = sin7pi/12]

=> on comparing both sides we find that A=7pi/12 and B=pi/12 which satisfies the  condition that  A+B  = 2pi/3

Hence ,
A=7pi/12
B=pi/12
C=pi/3



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