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Discussion Response Post to:
Properties Of Triangles
Forum Index
->
Trignometry
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Author
Message
28 Mar 2008 14:29:55 IST
Subject:
Re:Properties Of Triangles
Accepted Answer
[?]
Werewolf
(
333
)
Blazing goIITian
55
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84
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total posts:
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Since A+B+C=
=> A+B =
-C =
-
/3 = 2
/3.....[ the angles should satisfy this condition]
Now we have ,
a/b = tan5
/12
=> sinA/sinB = tan5
/12
=> sinA/sinB = ( sin5
/12 )/( cos5
/12 )
=> sinA/sinB = ( sin5
/12 )/( sin
/12 ) [ cos5
/12 = sin
/12]
=> sinA/sinB = ( sin7
/12 )/( sin
/12 ) [ sin5
/12 = sin7
/12]
=> on comparing both sides we find that A=7
/12 and B=
/12 which satisfies the condition that A+B = 2
/3
Hence ,
A=7
/12
B=
/12
C=
/3
"All of us are God's creatures... just some are more creature than others."
this reply: 10
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