for hybridisation: 1)first find the charge on the metal and write its e- config. 2)then pair e- if it is a strong ligand. 3)then take the orbitals of the metal ion which are empty. for eg:[Co(NH3)6]3+ Co3+=[Ar]4s0 3d6 || | | | |------>these r electrons representation since NH3 is strong pair it. || || || d d s p p p it implies der r two d ,one s and three p orbitals which r empty. so u have d2sp3 hybridisation. hope this helps do ask if not clear !!!!!!!!!!!!!!!!!!
Varsha
be cool,
tomorrow is what we make it today,
so if u can dream it , u can make it .
life is an ice cream ,eat it before it melts away!!!!!!!!!
Moderation Team
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