Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: tr eq 3
Forum Index -> Trignometry -> View Full Question Email  
Author Message
Priyesh (1601)

Blazing goIITian


Priyesh's Avatar

total posts: 1042    
Offline
hi joyfrancis the soln. is as follows
 
(1+cosx)(2sinx-cosx)=sin2x
2sinx-cosx+2sinxcosx-cos2x-sin2x=0
2sinx-cosx+2sinxcosx-1=0
1(2sinx-1)+cosx(2sinx-1)=0
(1+cosx)(2sinx-1)=0
cosx=-1
or
sinx=1/2
therefore
x=2npi +- pi
x=npi + (-1)npi/6
0 people liked this
 
Free Sign Up!

Preparing for IIT-JEE ?

Arihant Revision Package for IIT JEE - Books, Practice Tests + Rank Predictor


@ INR 1,995/-

For Quick Info

Name

Mobile No.

Sponsored Ads