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[Post New]29 Mar 2008 21:54:08 IST
    Subject: Re:Simple one integral calculus...
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uday_zingtudor (931)

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Olaaa!! Perrrfect answer. 155  [233 rates]
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Hey simple one!!

Write the expansion of log 1-x

It's log1-x = -x - x^2/2 - x^3/3 - x^$/4 - .....................


Now, log1-x/x implies  -1 -x/2 - x^2/3 - ............

Integrating this you get -x - x^2/4 - x^3/9 - x^4/16

From the given info the answer is - pie^2/6

Thank u

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