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Discussion Response Post to:
GIF Function
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Author
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29 Mar 2008 22:34:00 IST
Subject:
Re:GIF Function
uday_zingtudor
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well, the answer is zero if x belongs to [4npi,(4n+1)pi/2) U ((4n+1)pi/2,(4n+1)pi]
it's infinity if x= (4n+1)pi/2
it's minus infinity if x belongs to ((4n+1)pi,(4n+2pi))
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