60 Apply Law of conservation of angular momentum about centre we get mvL/2=ML2,/12,as particle stops after collision we get =6mv/ML M is mass of rod,m is mass of particle,v is velocity of particle as angular velocity is constant apply theta=t theta=/2 we get t=ML/12mv now apply law of conservation of linear momentum we get mv=MV V is velocity of centre of rod V=mv/M use s=Vt we get s=mv/M*ML/12mv we get s=L/12 answer Rate me if satisfied Nudge me for dought
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64
,/12,as particle stops after collision
/2
