|
|
|
|
|
| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 30 Mar 2008 13:52:58 IST
|
|
|
since it passes through x-axis it will meet it at (a,0). now eqn of line perp. to it will be given by ax+by=k putting (a,0)in this eqn we get k=a^2. therefore the eqn will be-ax+by=a^2
|
this reply: 2 points
(with 0 
in 1 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|
|
|
|
|
|