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![[Post New]](/templates/default/images/icon_minipost_new.gif) 30 Mar 2008 14:20:21 IST
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At equivalent point concentration of NaCN (c) = is 0.0325*45/(45+72.8)
If h is degree of hydrolysis then for recation
CN- + H2O --> HCN + OH-
equllibrium constant is Kh= Kw/Ka
Conc of [OH-]=ch
Conc of [HCN] = ch
conc of [CN-] = c(1-h)
if h<<1 then
h = sqrt(Kw/(Ka*c))
So [OH-] = sqrt(cKw/Ka)
use this to find pH
Conc. of [CN-] = c(1-h)
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Krishna Gopal Singh
B.Tech Chemical Engg
IIT Delhi 2002
Currently doing PhD from IIT Delhi |
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