let d capacitence b C1& capacitance on 2nd b C2 let charge on 1st capacitor b Q1& similarly Q2 since both capacitors r connected in series d effective capacitance is C=C1C2/C1+C2 hence charge on 1st capacitor isQ1=C x V1 hence charge on 2nd capacitor Q2=C x V2
apply d same u may get d answer plz do rate me if ur satisfied satisfied with my answer