1/(x+logx)

OKAY I GOT A METHOD,,, but wts wrong ? :
log x = t .............x = e^t
1/x dx = dt

1/(x+logx) = x / x (x+logx)
= e^t.dt / e^t + t

take e^t + t = m
e^t + 1 .dt = dm -------------------- OK mistake was here i took it as e^t.dt earlier thanks :D.... man really should stop staying awake late night lol

so integration = log m = log (e^t + t)
= log (x + log x)

but it seems wrong to me :(
sandeepramesh any clue?