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![[Post New]](/templates/default/images/icon_minipost_new.gif) 2 Apr 2008 09:28:49 IST
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Time of fall = sqrt(2*(2h-y)/g)
velocity = sqrt(2*g*y)
X=2*sqrt(y*(2h-y))
This has a max at y=h
X_max = 2h
So (a) is right answer
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Krishna Gopal Singh
B.Tech Chemical Engg
IIT Delhi 2002
Currently doing PhD from IIT Delhi |
this reply: 5 points
(with 1 
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