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ramyani (2532)

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Olaaa!! Perrrfect answer. 428  [624 rates]

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X (220) ->  Y ( 216 )  + alpha  ( 4 )

nucleus of mass number 220, initially at rest.  So conservation of momentum gives

0 = 216 v1  + 4 v2

v1 = - 4v2 / 216 =  -v2 / 54

now
conservation of energy gives

( 1/2) m1 v12  +
( 1/2) m2  v22  = Q

108  
v12 + 2  v2 2 = 5.5 mev

108 ( -v2 / 54 )2 + 2  v2 2 = 5.5 mev

 2  v2 2 =  5.4 Mev

** edited.


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