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[Post New]3 Apr 2008 23:17:47 IST
    Subject: Re:integration of
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sboosy (3053)

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\mbox{I am afraid that the answer given by Mr Edison might be incorrect} \\ \\ \mbox{To begin with we know} \ \sec^2x>=1 \\ \\ \mbox{Now we also know that definite integrals preserve inequalities.Thus} \\ \\ \int_0^\pi sec^2x\,dx \geq \int_0^\pi 1\,dx \\ \\ \Rightarrow \int_0^\pi sec^2x\,dx \geq \pi > 0 \\ \\ \mbox{Thus i think that the answer to this question cannot be} \ \tan(\pi) \ \mbox{which is} \ 0
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