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Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: newtons laws of motion............
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ganesha1991 (1642)

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Olaaa!! Perrrfect answer. 290  [386 rates]

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to the right the mass of rope = mass on left = M/2
there fore
T = [M +M/2]a=3/2Ma
or a =[ 2/3M ]T
for the right side
F- T=Ma
1-T = [2/3M]TM/2
1-T = T/3
[4/3]T=1
T=3/4 =0.75
 this reply: 2 points  (with Olaaa!! Perrrfect answer.   in 1 votes )   [?]
 
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