IIT JEE , AIEEE Forum - Mathematics , Integral Calculus

neeraj_agarwal_1990

when u do this...u r substituting tanx=t,=>sec^2xdx=dt....

but note that since tanx is discontinuous at pi/2, we can substitute its value...

for substituting a function,it should be continuous,differentiable and monotonous in the given interval...if not...then we have to apply jugad...

as anup said...
function is even, divide the upper limit by 2 and put 2 outside....

now its 2 [tanx] from 0 to pi/2 which is 2(infinity-0)=infinity...

so the given function does not converge....

also note that tanpi/2 is NOT DEFINED and its not infinity...but while calculating such integrals...we take the limiting value at that point....which is infinity in this case...

Ask & Discuss Questions with Community & Experts