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Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: newtons laws of motion............
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problemkiller0.1 (5)

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Olaaa!! Perrrfect answer. 1  [1 rates]

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F=2ma   and    F-N=ma(n is force acting                          and  N=ma
                                 on rope at other end)                   so F=2N
at mid point f rope                                                      
 
F-N'=ma\2    and        N'--N=ma\2
  so
      F--N'=N--N'    SO  F+N=2N'
 
                          N'=F+N\2    so  N'=F+F\2
                                                       -------
                                                          2
                                                                      SO   N'=0.75  IS AWNSER
 this reply: 5 points  (with Olaaa!! Perrrfect answer.   in 1 votes )   [?]
 
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