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![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Apr 2008 11:35:05 IST
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The reaction is NO + N2O + H2 = N2 + H2O
Apply POAC for N. let x be the vol of NO in the mix. then N2O= 60-x
x+ 2(60-x) = 2x38
solving for x, we get x= 44
so, NO= 44ml & N2O= 16ml
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