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Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: H.C.Verma - Work & Energy
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[Post New]5 Apr 2008 19:22:22 IST
    Subject: Re:H.C.Verma - Work & Energy
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uday_zingtudor (931)

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Olaaa!! Perrrfect answer. 155  [233 rates]
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51)Since the potential energy remains constant, Equate the energy in the spring at instant to the kinetic energy at the vertical position.

length of the spring at the given instant is h/cos37 = 5h/4

That means the elongation is h/4.

(1/2)kh2/16 = (1/2)mv2

You get the answer to be v=(h/4)(sqrt(k/m))

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