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Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: Summation
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[Post New]5 Apr 2008 20:12:49 IST
    Subject: Re:Summation
Accepted Answer [?] [Up]
sunip_the_mini_mastermind (133)

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Olaaa!! Perrrfect answer. 19  [38 rates]
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total posts: 208    
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yes the ans is i.
[r=1 ][ 8] sin (2r/9)+icos(2r/9)
=[r=1 ][ 8]-i2 sin (2r/9)+i cos(2r/9)
=-i[r=1 ][8 ] i sin (2r/9)+cos(2r/9)
=-i[r=1 ][ 8] ei2rpi/9
=-i[r=0 ][ 8] ei2rpi/9-1
=-i(sum of n powers of unity -1)      {sum of n powers of unity =0)
=i
 this reply: 5 points  (with 1 Olaaa!! Perrrfect answer.   in 1 votes )   [?]
 
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