now you have 4 ( x2 + 1/16) - 8cx + 3/4 = 0 solve for x ,
x = 8c (64 c2 - 12(4c2 - 1) / 8 ( 4 c2 - 1)
c is given 0
put the values of y and you get the complex number
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613
( x2 + y2)
( x2 + y2) - 4 c (x + iy) + 1+ ic = 0
0 
