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dev_22oct (1405)

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Olaaa!! Perrrfect answer. 257  [317 rates]

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dear your question is not complete. bt i knw that this is rorkee 1992 problem.
 
H2S--------> H+  +  HS-  Ka1= 10-7
 
HS---------> H+  +  S2-   Ka2 =1.3 x10-13
 
HCl----> H+ + Cl-
 
now due to common ion effect the dissociation of H2S is suppressed and the [H+] in the solution is due to HCl
 
Ka1  =  [H+][HS-]
           ---------------
             [H2S]
 
10-7  =[0.3][HS-]/[0.1]
 
Therefore [HS-]= 3.3 x10-8 M
 
Ka2 =[H+] [S2-]/[HS-]
 
Ka1 x Ka2 =[H+]2[S2]/[H2S]
 
Placing Ka1 and Ka2 in the obove expression we get [S2-] as 1.4x10-20 M
 
 

Devendra Kumar Shukla
M.Sc physical Chemistry
Currently working in Daswani classes
 this reply: 7 points  (with Olaaa!! Perrrfect answer.   in 2 votes )   [?]
 
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