--------->for a given no.  N=(P^m)(Q^n)(R^s)......whereP,Q,R are prime nos     then no. of divisors=(m+1)(n+1)(s+1)

5400=3^3.2^3.5^2

so no of divisors=(3+1)(3+1)(2+1)=4*4*3=48

including the no. & 1

-------->sum of divisors=(1+P^1+P^2+P^3+........P^m)(1+Q^1+Q^2+..........Q^n)(1+R^1+R^2+..............R^s)

5400  sum of divisors==(1+3+3^2+3^3)(1+2+2^2+2^3)(1+5+5^2)

                                =40*15*31=18600