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Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: work energy hc verma
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hsb (10)

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Olaaa!! Perrrfect answer. 2  [2 rates]

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total posts: 27    
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x= dist moved by a bfore losing contact
 
decrease in pe of system= mgx
 
loss in pe =gain in epe = ke of 2 blocks
 
mgx = 1/2 ka^2  +  mv^2
 
calc v^2  = gx - k/2m*a^2
 
 
when A loses contact  vert eqm      fcos = mg
 
f = k a
 
 
solving   a cos theta  =.08
 
 
L/a+L = COS THETA                cos theta = .1
 
 
calculate v

 this reply: 5 points  (with Olaaa!! Perrrfect answer.   in 1 votes )   [?]
 
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