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[Post New]6 Apr 2008 21:49:41 IST
    Subject: Re:trig..
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ramkumar_november (1270)

Blazing goIITian

Olaaa!! Perrrfect answer. 230  [290 rates]
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sin(A+B)sin(A-B)\;=\;sin^2A-sin^2B
 
so
 
sin(60+\theta)sin(60-\theta)\;=\;sin^2 60-sin^2 \theta
 
sin(60+\theta)sin(60-\theta)\;=\;\frac{3}{4}-sin^2 \theta
 
sin\theta sin(60+\theta)sin(60-\theta)\;=\;\frac{3sin\theta-4sin^3\theta}{4}
 
sin\theta sin(60+\theta)sin(60-\theta)\;=\;\frac{sin3\theta}{4}
 
this is the right formula.........
 
 
 
 
 this reply: 5 points  (with 1 Olaaa!! Perrrfect answer.   in 1 votes )   [?]
 
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