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[Post New]6 Apr 2008 23:21:35 IST
    Subject: Re:problem in kinamatics
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rathin_123 (55)

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Olaaa!! Perrrfect answer. 9  [14 rates]
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if they both do constant acc motion then &their acc is A
 
then    time t=root(D / A)
for p it meet q at D/2 as they both do con acc
THEIR u=0 so from D/2=ut+1/2 At^2
 
                             D/2=1/2 At^2
                            
                              t=root(D / A) 
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