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![[Post New]](/templates/default/images/icon_minipost_new.gif) 7 Apr 2008 06:14:21 IST
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2sin-1x * cos-1x = 3cos-1(1/ sqrt x) *sin-1(1/sqrt x)
since domain on LHS is x between -1 to 1.
and domain on RHS is x greater than equal to 1.
so boundary value is 1.
and 1 satisfies the equation , as cos -1( 1) is 0 in both LHS and RHS.
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* Gaurav Ragtah ( aka Artemis Fowl )
* Agent 'G' [sniper] - SD-6 (Alliance of Twelve)
* Your friendly neighborhood spideyunlimited |
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