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raulrag009 (1217)

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Olaaa!! Perrrfect answer. 205  [301 rates]

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Let   x-3y+ \mu =0  be the line perpendicular to 3x+y+1=0  {mu is a constant}
 
Since it passes through (2,1)
It must surely satisfy it.
 
2-3(1)+\mu=0\\\\
\mu=1
 
 
Thus ans is
x-3y-1=0
 
 this reply: 5 points  (with Olaaa!! Perrrfect answer.   in 1 votes )   [?]
 
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