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srujana (3132)

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Olaaa!! Perrrfect answer. 564  [720 rates]

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I think it should be P.T. tan X = 5tan B\ \ \ \Construct APperp DE,\ \Since angle ADE = angle AED = X, DP=PE


http://aycu01.webshots.com/image/51760/2003055639521025065_rs.jpg


tanX= rac{AP}{DP}\ \tanB= rac{AP}{BP}\ \Rightarrow AP=DP . tanX=BP . tanB\ \Rightarrow  rac{BC}{2}. tanX= rac{5BC}{2}. tanB  [BC = DE = EC= 2DP]\ \Rightarrow tanX=5.tanB

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