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Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: Permutations and combinations
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[Post New]7 Apr 2008 18:52:46 IST
    Subject: Re:Permutations and combinations
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sboosy (3063)

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Olaaa!! Perrrfect answer. 539  [723 rates]
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\mbox{Maximum no. of pts. of intersection of 2 circles is 2} \\ \\ \mbox{Now the next (3rd)circle can intersect the 2 drawn circles each at 2 distinct pts} \\ \\ \mbox{That accounts for 4 pts.Thus totally we have got 2+4=6 pts} \\ \\ \mbox{Now the fourth circle can intersect the drawn three each in 2 distinct pts.} \\ \\ \mbox{That accounts for 6 pts.Thus totally we have 6+6 =12 pts} \\ \\ \mbox{This way we see that we form an AP} \\ \\ \mbox{Thus the maximum no. of pts. of intersection of 8 circles is} \\ \\ 2+4+6+8+10+12+14 = 56
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