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[Post New]8 Apr 2008 11:38:34 IST
    Subject: Re:try this one - part 2
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srini (352)

Blazing goIITian

Olaaa!! Perrrfect answer. 56  [92 rates]
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total posts: 558    
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.Hey,
If x E I  => x2-x-2=0=>
                               x=-1 or 2
If x I  => x2-[x]-2=0   x2-x-2+{x}=0
           
                 Since for {x}:  0<{x}<1  => -1<x2-x-2<0 
                                   = -1<(x-1/2)2-9/4<0
    x-1/2> 5 /2    -3/2<x-1/2<3/2
 
Here, dont take integral solutions.
GIVE LIFE THE BEST....srini...
DO OR DIE, OR BETTER NEVER TRY!!
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 this reply: 2 points  (with 0 Olaaa!! Perrrfect answer.   in 1 votes )   [?]
 
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