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Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: try this one - part 2
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ashish_banga (966)

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Olaaa!! Perrrfect answer. 152  bad job dude!! I dont approve of this answer! 1  [257 rates]

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x^2 - 2 - [x] = x^2 - 2 -( x - {x} )

{x} = fractional part of x = - x^2 + 2 + x
as 0< {x} <1
0 < - x^2 + 2+ x < 1
solve to get answer it is simple afterwards

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