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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Apr 2008 20:19:40 IST
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1)
L1=2x-y=1 bisects line L2=y=mx+c and L3=y=x
let angle between L3 and L2=@
tan @= m2-m1/1+m1m2
tan @=(2-1)/(1+2)=1/3
now angle between L1 and L2 also =@
tan@=m-2/1+2m
1/3=(m-2)/(1+2m)
1+2m=3m-6
m=7
so y=7x+c
but the lines x=y and 2x-y=1 intersect at (1,1)
so y=7x+c passes through (1,1)
1=7+c
c=-6
so equation of line is
y=7x-6
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