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Discussion Response Post to:
Trigonometry IIT-JEE question
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9 Apr 2008 20:27:00 IST
Subject:
Re:Trigonometry IIT-JEE question
nknikhilesh1
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sin X + cos X=root2 sin(pi/4+theta)
sin X + cos
root 2 <pi/2 as root 2=1.414 and pi/2=1.57
sinX + cos X<pi/2
cos X<pi/2-sin X.........................(1)
takin sin on both sides of equation 1 we get the required result
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