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Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: D C Pandey Q frm rotational motion 2
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madman (239)

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Olaaa!! Perrrfect answer. 33  [70 rates]

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@arpan
parallel lines havent got opposite slopes
here is my solution
let the point be (x,y)
angular momentum of first particle = mvr1sin@ = mvp
angular momentum of second particle = mvr2sin@ = mvq
net angular momentum ( the angular momenta are in the same direction) = mvp+mvq =mvd (constant and independent of x and y)
you can also consider a point outside the lines
but in that case you will have to subtract them because they will be in opposite directions

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