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[Post New]11 Apr 2008 19:46:47 IST
    Subject: Re:Force displacement graph
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priyesh (1586)

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Olaaa!! Perrrfect answer. 256  [409 rates]
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from the graph F = (3/5)x
 
so work done from x = 2 to x = 8 is
 
[ 2][8 ]Fdx  =   3/5[2][8]xdx  = 3/10[ 64 - 4] = 18 J 
 
now this work done = change in kinetic energy = 1/2 * 2[v^2 - 3^2]
=> v^2 = 18 + 9  => v = root(27) = 5.2 m/sec
"Imagination is more important than knowledge."
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