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varsha valli g. (804)

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17)put a+bcosx=1
dt = -bsinx dx
cosx=(t-a)/b

substituting,v get i= (-2/b^2) *(t-a)/t^2

splitting into 2 integrals
i=(-2/b^2)(1/t - a/t^2)

now u can integrate it
i think the first term is a bit wrong in the ans u gave.
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