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Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: Please calculate-rate assured
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iit009 (24)

Cool goIITian

Olaaa!! Perrrfect answer. 4  [6 rates]

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total posts: 63    
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=Sin(?/14) Sin(3?/14) Sin(5?/14) Sin(7?/14) Sin(9?/14) Sin(11?/14) Sin(13?/14)
=Sin(?/14) Sin(3?/14) Sin(5?/14) Sin(?/2)sin(?-5?/14) sin(?- 3?/14)sin(?- ?/14)
=[ Sin(?/14) Sin(3?/14) Sin(5?/14)]^2
=[cos(?/2- ?/14)  cos(?/2-3?/14)  cos(?/2-5?/14)]^2
=[cos(3?/7) cos(2?/7) cos(?/7)]^2
= [cos(?/7) cos(2?/7) cos(3?/7)]^2
Multiplying and dividing by 2sin(?/7) we get
=[1/2sin(?/7)* (2sin(?/7) cos(?/7))* cos(2?/7) cos(3?/7)]^2
=[1/4sin(?/7)* (2sin(2?/7) cos(2?/7))* cos(4?/7)]^2
We can write cos(3?/7)=cos(?-4?/7)
                                         =cos(4?/7)
=[1/8sin(?/7)* (2sin(4?/7) cos(4?/7))]^2
=[ 1/8sin(?/7)* sin(8?/7)]^2
We can write sin(8?/7)=sin(?+?/7)
                                          = -sin (?/7)
=[1/-8]^2
=1/64            ( answer)
 this reply: 5 points  (with Olaaa!! Perrrfect answer.   in 1 votes )   [?]
 
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