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 Discussion Response Post to:
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 12 Apr 2008 15:11:57 IST
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let sinx = t3
then cosx dx = 2 t2 dt
it becomes
[ ] [ ] t X (2 t2/[ ] 1 - t6 ) dt
= 2 [ ][ ] t3 /[ ] 1 - t6 dt
now let t3 = z
it can now be solved easily
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