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shinee (247)

Blazing goIITian

Olaaa!! Perrrfect answer. 41  [62 rates]

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total posts: 640    
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can u plz integrate these
1)sec5xtanx    ans    1/5(sec5x)
2)(cos2x)/(sinx +cosx)2 =   ans   log lsinx+cosxl
3)(xe-1   +  ex-1 )/(xe   +   ex )  ans 1/e{logIxe +exl}
can u also tell me how(on wat basis)  we should  take substitutions like t,z etc
4)(sin2x)/(sin5xsin3x)  ans 1/3LogIsin3xI-1/5logIsinxI
5)(1-tanx)/(1+tanx)     ans  log Icosx+sinxI
6)cot3x  ans -1/2cot2x - log lsinxl
7)(sin2x)/(sin5xsin3x)   ans   1/3loglsin3xl  - 1/5 loglsin5xl
8)1/(a2sin2x + b2cos2x)  ans 1/ab(tan-1(atanx/b)
9)1/(ex + e-x )2   ans -1/(2(1+e2x ))
10) 1/(ex +1)(1+e-x )   ans -1/(1+ex )
11)(x+2)/ (1-x2 )        ans - (1-x2 )   + 2sin-x
12)cosec4x  ans  -cotx  -(cot3x)/3
13) tan3x   ans  -loglsecxl   +(tan2 x)/2

SHREYA
    
 

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