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Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: find the remainder ....................
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prateekdhariwal (25)

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Olaaa!! Perrrfect answer. 3  [8 rates]

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5^99 can b written as=(26-1)^49....by binomial expznsion we get=

x=5(26^49-49c1.26^48..........-1)
as divided by 13
x=( )+13
therefore
x=()-5+13
therefore the remainder is -5+13=8
 this reply: 15 points  (with Olaaa!! Perrrfect answer.   in 3 votes )   [?]
 
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