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Discussion Response Post to:
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Author
Message
15 Apr 2008 19:08:36 IST
Subject:
Re:an
cutie_divs91
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Hot goIITian
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answer to the first part is also similar to that of the second part i.e.-
u=4.50x10^5m/s
s=0.375m
a=F/m
=> a=Eq/m
put E= -1.50V/m(since direction is opposite)
q= -1.6x10^ -19C
m=9x10^9kg
then use the equation of motion -
v
2
=u
2
+2as
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