sign up I login
 advanced
refer a friend - earn nickels!!

Ask & Discuss Questions with Community & Experts

Moderation Team
Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: an
Forum Index -> Electricity -> View Full Question like the article? email it to a friend.  
Author Message
cutie_divs91 (58)

Hot goIITian

Olaaa!! Perrrfect answer. 10  [14 rates]

cutie_divs91's Avatar

total posts: 116    
offline Offline
answer to the first part is also similar to that of the second part i.e.-
 
u=4.50x10^5m/s
s=0.375m
a=F/m
=> a=Eq/m
 
put E= -1.50V/m(since direction is opposite)
q= -1.6x10^ -19C
m=9x10^9kg
 
then use the equation of motion -
 
v2=u2+2as
 this reply: 5 points  (with Olaaa!! Perrrfect answer.   in 1 votes )   [?]
 
You have to be logged on to rate
  
 

Top Offers for goIITians
Correspondence Courses
Brilliant Tutorials
Narayana Institute
Aakash Institute
Classroom/Crash Courses
Narayana - Kota , Delhi , Others
Brilliant Tutorials - Class , Crash
Aakash Institute - Medical , Engg
Online Test Series
Brilliant Tutorials
Narayana Institute
Aakash Institute
Mahesh Tutorials
AMITY      Sri Chaitanya