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Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: fghgjh
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[Post New]15 Apr 2008 19:22:16 IST
    Subject: Re:fghgjh
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sweet08 (72)

Cool goIITian

Olaaa!! Perrrfect answer. 12  [18 rates]
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 = -1/2 int (-2x/root1-x^2) +int( 2/root1-x^2)
= -1/2 (2 root 1-x^2)  + 2 sin(inv x)
= -root 1-x^2 +2sin(inv x) 
 this reply: 5 points  (with 1 Olaaa!! Perrrfect answer.   in 1 votes )   [?]
 
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